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Math Help - Turning a mgf into a pmf

  1. #1
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    Turning a mgf into a pmf

    this is given m(t) = (1/3) + (2/3)e^t


    m (t) = (.25 + .75e^t)^12

    How do these become pmf's and also what is the first and second derivative of the first one. Is it just 2/3 e^t?
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  2. #2
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    Quote Originally Posted by wolverine21 View Post
    this is given m(t) = (1/3) + (2/3)e^t


    m (t) = (.25 + .75e^t)^12

    How do these become pmf's and also what is the first and second derivative of the first one. Is it just 2/3 e^t? Mr F says: Yes.
    Ah yes. The recognition problem.

    Big hint: If X ~ Binomial(n, p) then m_X (t) = [(1 - p) + p e^t]^n
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