this is given m(t) = (1/3) + (2/3)e^t
m (t) = (.25 + .75e^t)^12
How do these become pmf's and also what is the first and second derivative of the first one. Is it just 2/3 e^t?
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this is given m(t) = (1/3) + (2/3)e^t
m (t) = (.25 + .75e^t)^12
How do these become pmf's and also what is the first and second derivative of the first one. Is it just 2/3 e^t?
Ah yes. The recognition problem.Quote:
Originally Posted by wolverine21
Big hint: If X ~ Binomial(n, p) then