Originally Posted by

**pentaquark** I have a problem concerning Russian Roulette. Not a personal problem, mind you, but a statistical one. The game is a sole player with 1 gun, 1 bullet and the chamber is spun each time. I believe I have MOST of what I need to solve the problem, but am unsure.

Starting with this probability eq:

$\displaystyle P(n)=N!/(n!*(N-n)!)*p^n*q^(N-n)$

I think I have the constants set out to be

N=# of rounds played

p= probability of getting the bullet=1/6

q=probability of getting empty round=5/6

If the question is what is the probability of still being alive after N rounds, I can't figure what n should be. I think with that, the problem should be solved, but I can't wrap my mind around what it should be.

ps. that's q to the (N-n) power, btw, I don't think it looks quite right