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Math Help - Me again

  1. #1
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    Me again

    What is the probability that a five-card hand is not void in any suit?
    Answer: .2637

    2 spades, 2 hearts, 1 diamond + 3 spades, hearts + all spades?

    Im at a loss here


    Four men and five women line up so that there is at most one pair of men standing next too each other?
    answer = 126,000

    5! women being anywhere
    4 choose 2 for how many different pairs of men there can be.
    4 possible spots for the pair of men to go?
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  2. #2
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    Quote Originally Posted by shootie300 View Post
    What is the probability that a five-card hand is not void in any suit?
    Answer: .2637

    2 spades, 2 hearts, 1 diamond + 3 spades, hearts + all spades?

    Im at a loss here

    [snip]
    1 - Pr(void in at least one suit).

    To calculate Pr(void in at least one suit), first read this thread: http://www.mathhelpforum.com/math-he...obability.html

    Now modify the argument for five cards rather than 13 cards.
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  3. #3
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    k

    I looked over it and know that 52 choose 5 is the amount of possible hands.
    4(39 choose 5) would be the number to void one card.

    What is the probability of a 5 card hand not being void in any suit?

    So I was looking to subtract... and couldnt find a way to get .2637, I got .22 sumthing
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