I have been working on these problems for a several hours and am stuck. Can anyone help me at all? Here are the problems:
A poker hand is defined as drawing five cards at random without replacement from a deck of 52 playing cards. Find the probability of each of the following poker hands:
A. Two pairs (two pairs of equal face value plus one card of a different value)
B. One pair (one pair of equal face value plus three cards of different values)
Hello, cb22hawk!
There are: . possible poker hands.A poker hand is defined as drawing five cards at random
without replacement from a deck of 52 playing cards.
Find the probability of each of the following poker hands:
A. Two pairs (two pairs of equal face value plus one card of a different value)
There are: . choices for the values of the pairs.
There are: . ways to get the two pairs.
And there are choices for the fifth card.
Hence, there are: . ways to get two pairs.
Therefore: .
B. One pair (one pair of equal face value plus three cards of different values)
There are: . choices for the value of the pair.
There are: . ways to get the pair.
There are: . choices for the other three cards.
. . (They must not contain another pair.)
Hence, there are: . ways to get one pair.
Therefore: .