Thread: Discrete random variable help!

The average number of children per Spanish couples was 1.34 in 2005. Suppose that one Spanish couple is chosen randomly.

a. Find the probability that they have no children.
b. Find the probability that they have fewer children than the Spanish average.
c. Find the probability that thety have more children than the Spanish average.

I can't figure out what to do. This is all that is given.

Originally Posted by Myung

The average number of children per Spanish couples was 1.34 in 2005. Suppose that one Spanish couple is chosen randomly.

a. Find the probability that they have no children.
b. Find the probability that they have fewer children than the Spanish average.
c. Find the probability that thety have more children than the Spanish average.

I can't figure out what to do. This is all that is given.

You don't have sufficient information to do this, you need to know the distribution for the number of children that a family has. Now it might be that you are supposed to assume a Poisson distribution, but that would be invalid.

RonL