Hey, all. Having a rough time with a couple of problems, here's one:
1) If X is chi-squared^2(12); that is, r = 12 sorry dunno the correct notation)
find constants a and b such that P(a <X<b)=0.90 and p(X<a)=0.05
I think I know how to set it up; the probability is given between a & b, so I need to integrate with bounds a & b, and set the integral equal to 0.9; likewise, I can from 0-->a and set it equal to 0.05
My problem is the integral. Is my pdf correct here:
f(x)= [x^5e^(-x/2)] / (6)(2^6)
So I'd be integrating 1/384* integral of x^5e^(-x/2) ??
How can I do that integral without doing integration by parts 5 times?? Thanks.