Originally Posted by

**Hypertension** ok, so I include the rolled numbers too?

so technically it would be,

P(A)= sum of even numbers: .(1,1) (1,3) (1,5) (2,2) (2,4) (2,6) (3,3) (3,5) (4,4) (4,6) (5,5) (6,6) (3,1) (5,1) (4,2) (6,2) (5,3) (6,4)

$\displaystyle =\frac{18}{36}$

P(B)= sum of numbers greater than nine: (4,6) (5,5) (5,6) (6,6) (6,4) (6,5)

$\displaystyle =\frac{6}{36}$

Then P(A and B) = $\displaystyle \frac{4}{36}$

So, P(A or B)=$\displaystyle \frac{18}{36} + \frac{6}{36} - \frac{4}{36}$

$\displaystyle =\frac{20}{36}$

$\displaystyle =\frac{5}{9}$