The second part of the question, still keeping the same mean and standard deviation, goes like this:

Calculate P(49.6<X<65.3) I converted each X into a z-score:

Z=65.3-58.2/ 12.55= 0.56

Z=49.6-58.2/ 12.55= -0.69

Then I looked up each z-score in a normal table in my statistics book to find the percentage that corresponds to each z-score: (Did I do my notation right, by the way?)

For z-score 0.56: P(0<X<0.56)= 0.2123

For z-score

-0.69: P(0<X

-0.29)= 0.1141

Mr F says:
Finding z-scores then looking in a normal table to find percentages/probability is easy, but I get lost here. I don't know how to "complete" the problem and answer what is being asked of me. Help please? What am I lost on?