Originally Posted by

**Deadstar** This things melting my head...

Find the probability that a bridge hand (of 13 cards) is void in **at least** one suit (i.e. contains no cards of that suit)

So... The ways ive tried to do this filled 9 pages so ill try summarise.

The number of different ways 13 cards can be chosen from a 52 card pack is roughly $\displaystyle 6.35$x$\displaystyle 10^{11}$ (i think, im doing this from memory) so ive tried to figure out the number of hands that involve all 4 suits and also the number of hands that involve only 1,2 and 3 suits. Cant figure out any of these tho...

Couple of other ways that i cant remember, dont have my sheets with me, Can anyone give an answer with working? (by the way the answer is 0.051)

Cheers