Find a , given that 3,0,a,a,4,a,6,a and 3 have a mean of 4
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Originally Posted by lozza_55 Find a , given that 3,0,a,a,4,a,6,a and 3 have a mean of 4 What you are given is: $\displaystyle \mu=(3+0+a+a+4+a+6+a+3)/9=(16+4a)/9=4$ Now solve for $\displaystyle a$ RonL
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