Hi,
Let f(x,y) = 3/2 if 0<=x<=1 and x^2<=y<=1; otherwise f(x,y)=0
Find
P(X=1/4, 0<y<3)
So I know I'm suppose to do double integration. My bounds for x are from 0 to 1/4. The less than sign on y is confusing me. Should I take the integration of y from 0+x to 3-x?
Thanks.