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Math Help - Level of Signifigance question

  1. #1
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    Wink Level of Signifigance question

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    The Maine Department of Natural Resources reported that the mean weight of lobsters trapped in the state is 1.7 pounds. Shelly is a lobster trapper off the coast of Maine. She suspects that this figure is too high so she records the weights of a random sample of 45 lobsters that she trapped. If x = 1.5 pounds and s = 0.6 pounds, use a 1 percent level of significance to test the state's figure of 1.7 pounds.

    George and John wants to check the claim that convicted burglars spend an average of 20 months in jail. They have a random sample of 32 such cases taken from court files and find that = 18 months and s = 8.5 months. Test the null hypothesis that = 20 at the 0.05 significance level.
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  2. #2
    Bar0n janvdl's Avatar
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    Quote Originally Posted by badgrgal View Post
    Help!

    Please show me how you got the answer!

    The Maine Department of Natural Resources reported that the mean weight of lobsters trapped in the state is 1.7 pounds. Shelly is a lobster trapper off the coast of Maine. She suspects that this figure is too high so she records the weights of a random sample of 45 lobsters that she trapped. If x = 1.5 pounds and s = 0.6 pounds, use a 1 percent level of significance to test the state's figure of 1.7 pounds.

    George and John wants to check the claim that convicted burglars spend an average of 20 months in jail. They have a random sample of 32 such cases taken from court files and find that = 18 months and s = 8.5 months. Test the null hypothesis that = 20 at the 0.05 significance level.
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  3. #3
    Eater of Worlds
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    I ran this through my handy dandy statistics Excel sheet. I will leave it up to you to crunch the numbers. But, here are the results. Okey-doke?.

    Since she thinks it's too high it is a left-tail test.

    H_{0}:{\mu}\geq{1.7}

    H_{a}:{\mu}<1.7, \;\ claim

    The test statistic is -2.2361

    Critical value is -2.3263

    p-value is .0152

    Since the the alpha level of .01 is less than the p value, we fail to reject H_0.

    Also, as can be seen from the tst stat, it is not in the rejection region, therefore, we fail to reject.

    Since we fail to reject, there is not enough evidence at the .01 level to support the claim.
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