http://i235.photobucket.com/albums/e...4/untitled.jpg

No idea how to do part (a). Can someone please help me? Thanks!

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- Apr 22nd 2008, 08:53 PMcirrus74Finding the pmf from the distribution function
http://i235.photobucket.com/albums/e...4/untitled.jpg

No idea how to do part (a). Can someone please help me? Thanks! - Apr 23rd 2008, 03:42 AMCaptainBlack
I think we will have to assume that the possible values of $\displaystyle x$ are integers, then:

(a) well obviously we have:

$\displaystyle p_X(x)=0,\ x<-1$

and

$\displaystyle p_X(x)=0,\ x \ge 1$,

so that leaves only $\displaystyle p_X(-1)$ and $\displaystyle p_X(0)$ to be determined, can you do that?

RonL - Apr 23rd 2008, 08:25 PMcirrus74
Well actually, the answer that was given to us was:

http://i235.photobucket.com/albums/e...untitled-1.jpg

But I don't know how they got it? - Apr 23rd 2008, 08:36 PMCaptainBlack