Mr F says: This is a worry since it should equal 1 if f(x, y) is a valid pdf! Luckily it does: . Note: This calculation is NOT relevant for testing independence, but it does confirm that f(x,y) is a valid pdf.
now to test independence to I just multiply and very if it equals the the integrated form of
To test independence, you look to see if f(x, y) = f(x) f(y) ....