Originally Posted by
somestudent2 Suppose Y has density function:
f(y) = ky(1-y) when 0<=y<=1
and
f(y)= 0 elsewhere
[snip]
c)Find P(Y<=0.4|Y<=0.8)
d)Find P(Y<0.4|Y<=0.8)
[snip]
c) d) is where I have the problem. I suppose both must have the same answer.
Since this is conditional probability can we state that:
P(Y<=0.4|Y<=0.8) = [P(y<=0.4) AND P(y<=0.8)]/P(y<=0.8) = P(0.4<=Y<=0.8)/P(y<=0.8)
so I find using integral P(0.4<=Y<=0.8)=0.544
and P(y<=0.8) = P(0<=y<=0.8)=0.896
then we divide 0.544/0.896= 0.607
I feel that I am doing something wrong here, but can't see what.