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Math Help - A quick question...

  1. #1
    Newbie
    Joined
    Mar 2008
    Posts
    9

    A quick question...

    Can someone please give me a boost on how to solve these kind of problems? Are they all solved with the same formula or do you know what they are 'called' so I can google the concept? THANK YOU!!!!!!

    If P(0<z<a)=0.3212 (a is positive), find a?
    a)0.2
    b)0.02
    c)0.9
    d)0.92

    If P(-b<z<b)=0.3182 (b is positive), find b?
    a)0.41
    b)0.42
    c)0.39
    d)0.44

    If P(z>c)=0.2358 (c is positive), find c?
    a)0.71
    b)0.70
    c)0.72
    d)0.27

    What is the P(z>2.58)?
    a)0.5194
    b)0.4951
    c)0.4915
    d)0.0049

    What is the P(0.34<z<2.67)?
    a)0.4099
    b)0.0863
    c)0.4915
    d)0.4962
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  2. #2
    Senior Member
    Joined
    Feb 2008
    From
    Berkeley, Illinois
    Posts
    364
    Quote Originally Posted by aawb9c View Post
    Can someone please give me a boost on how to solve these kind of problems? Are they all solved with the same formula or do you know what they are 'called' so I can google the concept? THANK YOU!!!!!!

    What is the P(z>2.58)?
    a)0.5194
    b)0.4951
    c)0.4915
    d)0.0049

    If P(0<z<a)=0.3212 (a is positive), find a?
    a)0.2
    b)0.02
    c)0.9
    d)0.92

    You want to search for Z-scores to learn about this one. I'm looking into the other ones.

    I match your first answer for 0.0049, go here:

    Probability of a Random Variable in the Normal Distribution

    Press Probability Greater than, and enter 2.58, Press Calculate. It will show you the math.

    The general consensus for Z-scores is people grab values from a pre-approved table and go from there.

    2nd question I quoted, answer is d, use the same link. this time, use the Probability between button, 2 values come from your question, 0 and 0.92

    If P(z>c)=0.2358 (c is positive), find c?
    a)0.71
    b)0.70
    c)0.72
    d)0.27

    Answer is D. Same link I provided

    For the other questions, I think it's a similar concept, however I'm not sure if it's the same distribution. I think you have enough to get started, let me know if you have questions.
    Last edited by mathceleb; March 27th 2008 at 12:54 PM.
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  3. #3
    Newbie
    Joined
    Mar 2008
    Posts
    9

    Smile Yay!

    You are a rock star, thank you so very much! You bailed me out last time too! I am taking my statistics classes part 1 & 2 ONLINE at University of Phoenix which is why this is super confusing! Thanks for helping!

    Ashley
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