Thread: indicated probability

the september energy consumption levels for single family homes are found to be normally distributed with a mean of 1050 kwh and a standard deviation of 218 kwh.. for a randomly selected home, find the probability that the september engergy consumption level is between 1100 and 1225 kwh?

Originally Posted by momodagreat

the september energy consumption levels for single family homes are found to be normally distributed with a mean of 1050 kwh and a standard deviation of 218 kwh.. for a randomly selected home, find the probability that the september engergy consumption level is between 1100 and 1225 kwh?

Let X be the random variable September energy consumption.

Calculate Pr(1100 < X < 1225).

I get 0.1982 (correct to four decimal places).

Without knowing how you've been taught to calculate such probabilities (using tables, technology such as TI-84 or TI-89 calculators) it's impossible to provide further relevant help.