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Math Help - indicated probability

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    indicated probability

    the september energy consumption levels for single family homes are found to be normally distributed with a mean of 1050 kwh and a standard deviation of 218 kwh.. for a randomly selected home, find the probability that the september engergy consumption level is between 1100 and 1225 kwh?
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    Quote Originally Posted by momodagreat View Post
    the september energy consumption levels for single family homes are found to be normally distributed with a mean of 1050 kwh and a standard deviation of 218 kwh.. for a randomly selected home, find the probability that the september engergy consumption level is between 1100 and 1225 kwh?
    Let X be the random variable September energy consumption.

    Calculate Pr(1100 < X < 1225).

    I get 0.1982 (correct to four decimal places).

    Without knowing how you've been taught to calculate such probabilities (using tables, technology such as TI-84 or TI-89 calculators) it's impossible to provide further relevant help.
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