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Math Help - Clearification on Poisson Distribution

  1. #1
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    Clearification on Poisson Distribution

    Q: A parking lot has 2 entrances. Cars arrive at entrance 1 and 2 according to a Poisson distribution an average of 3/hour, and entrance 2 at an average of 4/hour, respectively. What is the probability that a total of 3 cars will arrive at the parking lot in a given hour? (assume arrivals are independent at the 2 entrances).

    Solution:

    \begin{array}{l}<br />
\lambda_p = \lambda_1 + \lambda_2 = 3+4 = 7 \\ \\<br />
P(3) = \frac{7^3}{3!} e^{-7} =0.0521295\\<br />
\end{array}

    Is this correct?
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by lllll View Post
    Q: A parking lot has 2 entrances. Cars arrive at entrance 1 and 2 according to a Poisson distribution an average of 3/hour, and entrance 2 at an average of 4/hour, respectively. What is the probability that a total of 3 cars will arrive at the parking lot in a given hour? (assume arrivals are independent at the 2 entrances).

    Solution:

    \begin{array}{l}<br />
\lambda_p = \lambda_1 + \lambda_2 = 3+4 = 7 \\ \\<br />
P(3) = \frac{7^3}{3!} e^{-7} =0.0521295\\<br />
\end{array}

    Is this correct?
    Yes

    RonL
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