help bivariate

• Mar 22nd 2008, 03:42 AM
gracey
help bivariate
Five observations of bivariate data produce the following results, denoted as (xi, yi)for i =1, 2, 3, 4, 5.

(13, 2.7) (13, 4.0) (18, 2.8) (23, 3.3) (23, 2.2)

[Σ x = 90, Σ y = 15.0, Σ x2 = 1720, Σ y2 = 46.86, Σ xy = 264.0.]

The regression line of y on x has gradient −0.06,
and its equation is y= 4.08 - 0.06x

The numbers e1, e2, e3, e4, e5 are defined by
ei = a +bxi −yi for i = 1, 2, 3, 4, 5.

The values of e1, e2 and e3 are 0.6, −0.7 and 0.2 respectively. Calculate the values of e4 and e5.

thanks (Talking)(Speechless)(Nod)
• Mar 22nd 2008, 03:51 AM
mr fantastic
Quote:

Originally Posted by gracey
Five observations of bivariate data produce the following results, denoted as (xi, yi)for i =1, 2, 3, 4, 5.

(13, 2.7) (13, 4.0) (18, 2.8) (23, 3.3) (23, 2.2)

[Σ x = 90, Σ y = 15.0, Σ x2 = 1720, Σ y2 = 46.86, Σ xy = 264.0.]

The regression line of y on x has gradient −0.06,
and its equation is y= 4.08 - 0.06x

The numbers e1, e2, e3, e4, e5 are defined by
ei = a +bxi −yi for i = 1, 2, 3, 4, 5.

The values of e1, e2 and e3 are 0.6, −0.7 and 0.2 respectively. Calculate the values of e4 and e5.

thanks (Talking)(Speechless)(Nod)

ei = (4.08 - 0.06 xi) - yi.

Just substitute (23, 3.3) and (23, 2.2) to get e4 and e5.
• Mar 22nd 2008, 04:03 AM
gracey
thank you sooo much you are absolutely amazing.
• Mar 22nd 2008, 04:09 AM
mr fantastic
Quote:

Originally Posted by gracey
thank you sooo much you are absolutely amazing.

Fantastic, actually. My brother is Amazing (Wink).

ps. you're welcome (Cool)