Let X be a random variable with probability density function: f(x)= (3/4)(1-x^2), -1 < x < 1 0, otherwise What is the standard deviaton of x?
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Originally Posted by chaddy Let X be a random variable with probability density function: f(x)= (3/4)(1-x^2), -1 < x < 1 0, otherwise What is the standard deviaton of x? You need to calculate E(X) and E(X^2): Then variance
Okay, so where Thus Is that right? Then but I am not sure how to find that last integral?
Originally Posted by chaddy Okay, so where Thus Is that right? Then but I am not sure how to find that last integral? When you're working with pdf's it's assumed you can integrate. So you need to thoroughly revise basic integration techniques. . This result could be anticipated since you're integrating an odd function ..... .
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