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Math Help - Changing variance on N(0,1)

  1. #1
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    Changing variance on N(0,1)

    Sorry folks...

    What I posted here was so bad and wrong that I cannot keep it. It's shameful...

    Therefore I remove it.

    My sincere apologies for removing the original posting.
    Last edited by paolopiace; March 10th 2008 at 11:23 PM. Reason: It was a pure non sense...
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  2. #2
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    This is not true in general. Choose x=0, then:

    <br />
\sigma^2\ e^{-\frac{x^2}{2}} = \sigma^2\ e^{-\frac{0^2}{2}} = \sigma^2<br />

    while:

    e^{-\frac{x^2}{2 \sigma^2}} = e^{-\frac{0^2}{2 \sigma^2}} = 1
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  3. #3
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    iknowone, Thanks.

    I got that what I wrote is totally wrong...

    I'm going to remove that shameful posting.

    The correct way to write it is:

    <br />
N(0,\sigma^2) = \frac{1}{\sigma} \phi\left(\frac{x}{\sigma}\right)<br />
    where

    <br />
\phi\left(x\right) = N(0,1)<br />
    Last edited by paolopiace; March 10th 2008 at 11:20 PM. Reason: Updating...
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