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  1. #1
    Newbie sweetkendra's Avatar
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    Unhappy how many ways could you

    Having a bit of trouble here:

    There are 7 seals and 8 dolphins entered in an aquatic obedience show. How many ways could you select a final group to judge if it must consist of 3 seals and 3 dolphins? How many ways could you award first, second and third place winners?

    I am not sure if you have to subtract three from each one on the first question or what? Really stuck.
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  2. #2
    Eater of Worlds
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    There are 7 seals and 8 dolphins entered in an aquatic obedience show. How many ways could you select a final group to judge if it must consist of 3 seals and 3 dolphins
    You must choose 3 seals from 7 and 3 dolphins from 8.

    C(7,3)*C(8,3)
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  3. #3
    Newbie sweetkendra's Avatar
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    Thank you

    Thank you for your help. What about the second part of the question or is it done the same way?
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    Quote Originally Posted by sweetkendra View Post
    What about the second part of the question or is it done the same way?
    Kendra,
    Do you plan to do any of your own work?
    Can you at least make some effort?
    If so, show us your work.
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  5. #5
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    Quote Originally Posted by sweetkendra View Post
    Having a bit of trouble here:

    There are 7 seals and 8 dolphins entered in an aquatic obedience show. How many ways could you select a final group to judge if it must consist of 3 seals and 3 dolphins? How many ways could you award first, second and third place winners?

    I am not sure if you have to subtract three from each one on the first question or what? Really stuck.
    Are the places being awarded to the six sea creaures chosen?

    Use the pigeon hole principle to get the number of ways of arranging six objects among three prizes ...... (6)(5)(4) = 120.
    Last edited by mr fantastic; February 25th 2008 at 09:45 PM. Reason: Deleted the last sentence - it was wrong.
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