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Thread: Poisson process problem

  1. #1
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    Poisson process problem

    I'm struggling with this question.

    The solutions are:

    a) 0.185
    b) 0.761

    But I don't know how to get to them. I appreciate your help.

    Poisson process problem-img_1418.jpg
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  2. #2
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    Re: Poisson process problem

    a) $p=P[\text{at least 5 calls}] = 1 - P[\text{4 calls or less}] = 1 - \sum \limits_{k=0}^4 \dfrac{(3)^k e^{-3}}{k!} = 0.184737$

    b) using $p$ from part (a) this is just a binomial distribution $n=7, ~p$

    $P[\text{at least 1 cell gets 5 calls}] = 1 - P[\text{0 cells get 5 calls}] = 1 - (1-p)^7 = 0.760622$
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  3. #3
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    Re: Poisson process problem

    Thanks a lot!
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