I don't think so. Let X be the random variablenumber of customers who want an.oversizeracket

Then the probability that the next ten customers get the racket they want is .

Note: If less than 3 customers want the oversize, then more than 7 want the midsize and someone's gonna miss out .....

Now note that X ~ Binomial(n = 10, p = 0.6).

Therefore