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Math Help - probability

  1. #1
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    probability

    Let  A be people who are high risk,  B be people who are medium risk, and  C be people who are low risk.



    Lets say  P(A) = p, \ P(B) = q, \ P(C) = r and the proportion of those in  A is  \hat{p} , those in  B is  \hat{q} , and those in  R is  \hat{r} , where  \hat{p} + \hat{q} + \hat{r} = 1 .



    So  P(\text{high risk and in the group}) = p(\hat{p})

     P(\text{person at risk}) = p(\hat{p}) + q(\hat{q}) + r(\hat{r}) and

     P(\text{randomly chosen person is high risk}) = \frac{ p(\hat{p})}{p(\hat{p}) + q(\hat{q}) + r(\hat{r}) } ?
    Last edited by heathrowjohnny; February 9th 2008 at 11:17 PM.
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  2. #2
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    would it just be  p and  \hat{p} ?
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  3. #3
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    or is this a poorly worded question?
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  4. #4
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    What's your question? Because the you answered then 3 questions written correctly.
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  5. #5
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    oh ok, so its correct?
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  6. #6
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    yeah i think so... I've been doing probability all day so it is possible i'm not seeing this right but i'll keep looking and post if i change my mind
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