So I've got data from a reflux ratio

0.78, 0.79, 0.87, 0.91, 0.92, 0.92, 0.92, 0.93, 0.94, 0.95, 0.95, 0.95, 0.95, 0.96, 0.96, 0.96, 0.97, 0.97, 0.97, 0.99, 0.99, 0.99, 0.99, 0.99, 0.99

I've been asked to get the probability less or equal to 0.94. This is fine, take the mean(0.94) and it's SD(0.0557), find the Z value and you get 0.5000 = 50%

However now it's asking me to find the probability of observing a response of 0.94 or less if it's assumed the data comes from a Weibull distribution.

I know the CDF is 1-e^-(lambda(x))^beta

However I'm not really sure how I generate those parameters? or how I go about this?

Can anyone assist me please?