How can write 'Inverse CDF' with the below CDF?
I picked a number. x = 22.
In your first post you posted a formula for F(x). This gives F(22) = 0.
In your second post you posted a formula for . Using this I get is undefined. So there is no inverse element for x = 22.
If you restate your original definition of to include u = 0 then you run into my original objection: as before, but now . It should give back our original number x = 22.
However the pdf that determines it is finite (discrete):
I am greatly puzzled by this question. In years of teaching this material. I have seen the inverse of a CDF called for nor have I ever had the need for such. I would like to read the exact original question.
Look at this page. As you can see there is no standard definition for inverse transform. Having taught probability/math-stat for many years, it is strange not to have ever seen the concept. If it is unique to your course you do well to find a computer science help site.
For a discrete distribution like this you wouldn't really consider the actual values on the real line other than to define bins. These bins then become the discrete support for the distribution. There is a 1 to 1 map from a bin to a probability value.
[QUOTE=Prove It;910864]I see a fundamental problem with this question...
As romsek said that is a necessary property of a probability density function, PDF.
A CDF is a monotonically increasing, right-continuous function that maps onto $(-\infty,\infty)\to [0,1]$.
BTW. Thank you romsek for the clarification on the inverse transformation. However, I did check what I think of as two standard applied statistics texts. But neither of those discussed anything about that topic. What is a good reference for this topic?