1. probability

find the probability of getting between 3 and 6 heads inclusive in 10 tosses of a fair coin by using

a the binomial distribution

b normal approximation to the binomial distribution

thanks for any help

btw i have 0.205 for part a

2. Originally Posted by question
find the probability of getting between 3 and 6 heads inclusive in 10 tosses of a fair coin by using

a the binomial distribution
we already addressed this in another one of your posts recently. you want P(3) + P(4) + P(5) + P(6)

b normal approximation to the binomial distribution
how is your knowledge of the binomial distribution? i can tell you $Bin(n,p) \approx Norm(np,npq)$ does that help? (n,p and q have the same definition as in part (a))

3. Originally Posted by Jhevon
we already addressed this in another one of your posts recently. you want P(3) + P(4) + P(5) + P(6)

how is your knowledge of the binomial distribution? i can tell you $Bin(n,p) \approx Norm(np,npq)$ does that help? (n,p and q have the same definition as in part (a))
knowledge is very hazy, used to be extremely proficient in the probability area but havent been near it in a long time so finding it a bit tricky

for part a i have 0.773 happy enough with that

for part b i have the formula z = (r-Np)/(npq)^0.5

should i just apply this, i have done so and expected the two answers to correlate somewhat but they arent