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Thread: Help Please

  1. #1
    jaskub05
    Guest

    Exclamation Help Please

    Please help me figure out this problem! I just can't figure it out!

    A 4-person grievance committee is to be composed of employees in 2 departments, A and B, with 15 and 20 employees respectively. If the 4 people are selected at random from the 35 employees, what is the probability of selecting:
    1) 3 from A and 1 from B
    2) 2 from A and 2 from B
    3) All from A
    4) At least 3 from A
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  2. #2
    MHF Contributor

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    The following gives the probability in terms of the number from A.
    $\displaystyle P(A = k) = \frac{{\left( {\begin{array}{*{20}c}
    {15} \\
    k \\

    \end{array} } \right)\left( {\begin{array}{*{20}c}
    {20} \\
    {4 - k} \\

    \end{array} } \right)}}
    {{\left( {\begin{array}{*{20}c}
    {35} \\
    4 \\

    \end{array} } \right)}},\;\;k = 0,1, \cdots 4$

    To answer the first one, let k=3.
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