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Math Help - Help Please

  1. #1
    jaskub05
    Guest

    Exclamation Help Please

    Please help me figure out this problem! I just can't figure it out!

    A 4-person grievance committee is to be composed of employees in 2 departments, A and B, with 15 and 20 employees respectively. If the 4 people are selected at random from the 35 employees, what is the probability of selecting:
    1) 3 from A and 1 from B
    2) 2 from A and 2 from B
    3) All from A
    4) At least 3 from A
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  2. #2
    MHF Contributor

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    The following gives the probability in terms of the number from A.
    P(A = k) = \frac{{\left( {\begin{array}{*{20}c}<br />
   {15}  \\<br />
   k  \\<br /> <br />
 \end{array} } \right)\left( {\begin{array}{*{20}c}<br />
   {20}  \\<br />
   {4 - k}  \\<br /> <br />
 \end{array} } \right)}}<br />
{{\left( {\begin{array}{*{20}c}<br />
   {35}  \\<br />
   4  \\<br /> <br />
 \end{array} } \right)}},\;\;k = 0,1, \cdots 4

    To answer the first one, let k=3.
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