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Math Help - Suppose a non bias coin was tossed two times?

  1. #1
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    Suppose a non bias coin was tossed two times?

    how would you do a random variable problem like this

    suppose a non bias coin was tossed two times
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  2. #2
    Senior Member DivideBy0's Avatar
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    Quote Originally Posted by jim1174 View Post
    how would you do a random variable problem like this

    suppose a non bias coin was tossed two times
    Well... let x be the random variable. You could make it stand for the number of times heads appeared.

    Pr(X=x) would then be the probability that x heads appeared.

    Pr(X=0) = 1-\left(\frac{1}{2}\right)^2 = \frac{3}{4}xxx
    Pr(X=1)=\frac{1}{2}
    Pr(X=2) = \left(\frac{1}{2}\right)^2 = \frac{1}{4}

    Since the coin is non-biased these same probabilities would appear if you set x as the number of tails that appeared.

    Is this what you wanted?
    Last edited by DivideBy0; December 5th 2007 at 01:25 AM.
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  3. #3
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    Error

    DividyBy0,

    Shouldn't it be Pr(X=0) = \left(1-\frac{1}{2}\right)^2 = \frac{1}{4}, not Pr(X=0) = 1-\left(\frac{1}{2}\right)^2 = \frac{3}{4} ?

    --Kevin C.
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  4. #4
    Senior Member DivideBy0's Avatar
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    yeah, you're right
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