Thread: Seating Arrangement Problem

I need some help with two problems. The first, I don't even know how to approach...

Three married couples are seated randomly in a row of six seats. What is the probability that no wife and husband are seating next to one another?



The second problem...

On average, how many chocolate chips should a cookie contain if the probability that a cookie contains at least one chip is to be at least .99?

I'm pretty sure that this is a poisson problem

where the entire expression is equal to .99, k = 1, and I have to solve for lambda. The problem is that I don't know how to solve for lambda in




Can anyone help me?

Originally Posted by valosn

I need some help with two problems. The first, I don't even know how to approach...

Three married couples are seated randomly in a row of six seats. What is the probability that no wife and husband are seating next to one another?

the total number of seating arrangements is 6!

it is easier to find the arrangement where every husband does sit next to his wife. to do this, we can consider each couple as one object with a permutation of 2! (since the wife can sit on the right or left of the husband). Thus we have 3 objects, each with a permutation of 2!. thus the number of seating arrangements where each husband sits next to his wife is 2!3!

so what is the probability of each husband sitting next to his wife? Hence, what is the probability that no husband sits next to his wife?

Allow to denote the case couple i is seated together. Then is the complement of that event. Now you want .