HI! I need help to find some answers!

What is the probability that if you roll a single standard die four times you will roll four different numbers?

5/18, 240/1296, 1/3 or none of these?

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- Nov 28th 2007, 09:12 AM #1K.S. TurnerGuest

- Nov 28th 2007, 11:15 AM #2

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The first die can be any of six values, the second any of the remaining five

and the third any of the remaining four and so on. So there are $\displaystyle 6\times 5 \times 4 \times 3 $

ways of rolling four dice so they are all different, and $\displaystyle 6^4$ ways of rolling the

die without constraint.

So the required probability is $\displaystyle 6 \times 5 \times 4 \times 3/6^4 =5/18$

RonL

- Nov 29th 2007, 01:56 AM #3

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- Nov 30th 2007, 03:59 AM #4

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