Hi All,

i want to find out set/case in following situation.

there are three number.{1,2,3}

"1" has too options,(exist or not exists and it will be less than "3")

"2" has four options, it can be less than "1" , greater than "1" and less than "3", greater than "3" and exist or not exist.

"3" has too options,(exist or not exists and it will be greater than "1")

"all are numbers 1,2,3 are optinal".

please suggest my solutions are correct or not

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Q1) will it be 3*4*3=36 ?

Q2 now i want to know, what combination can be made,

i can make three sets like

(1,2,3),(2,1,3),(1,3,2) based on above explanation( becase

then i can find sets of each one seprataly, then should decide which suite my case.

"or there is any systematic way"?

Q3) other thing is , it is quite eazy to find them manually for small numbers, how can i find it for big number , please solve one problem so that i can undersatand.

yours sincerley