No. The probability of D occurring overall may be tiny across the entire range of $\theta$. It's an integral when $p(\theta)$ is a probability density function rather than a discrete probability distribution.
No. The probability of D occurring overall may be tiny across the entire range of $\theta$. It's an integral when $p(\theta)$ is a probability density function rather than a discrete probability distribution.
Thankyou! So, it's just because it is a continuous distribution?
It looks similar to marginal likelihood, can I ask how this comes into play?
Thankyou
Thankyou! So, it's just because it is a continuous distribution?
It looks similar to marginal likelihood, can I ask how this comes into play?
Thankyou
Yes, because it's a continuous distribution.
If the distribution depended on parameters other than $\theta$ then yes this would be a marginal distribution, but since it doesn't you end up with just a value which is the probability of D occurring at all.