Originally Posted by

**AwesomeHedgehog** Yeah, sorry about that. When you used the notation, N(μ, σ), I have never seen that before, so I wasn't completely understanding what it was.

So, after searching it up online, I found out it's the standard normal distribution. So, I'm assuming that I just plug μ = 4, σ = 0.3849, and n = 9 into the normal distribution formula.

N(μ, σ) = (x - μ)/σ = 12.99

So, plugging that into the integral, I'd get:

The integral going from 5 to 6 of 12.99*x dx = 71.445

I did 5 to 6 since f(y) is between 2 and 6