Now I keep getting 21.65064519 as my answer. This is what I did:
The integral from 5 to 6 of (x^2 - μx)/σ dx = (182-33μ)/6*σ
Plugging μ and σ into that, I then got the 21.65 above. I didn't get what you got.
no...
you don't know what the Normal distribution is? I don't see how you can be trying these problems without knowing that.
$\large N(\mu,\sigma)=\dfrac{1}{\sqrt{2\pi}\sigma}e^{-\dfrac{(x-\mu)^2}{2\sigma^2}}$
and you can't just integrate it you have to look it up in a table or use software or something. You didn't go over any of this in class? It's not in your book at all?