• Oct 12th 2013, 02:04 PM
phys251
F(x, y) = 1 - e^-x - e^-y + e^(-x-y), x>0, y>0. I am supposed to find P(X + Y > 3).

I am messing up somewhere along the way, and I don't know where. What I'm doing is:
1. Finding f(x, y) = F_xy(x, y), which comes to e^-x * e^-y.
2. Setting P(X + Y > 3) = 1 - P(X + Y <= 3).
3. Setting P(X + Y <= 3) = $\int_0^3 \int_0^{3-x} {e^{-x} e^{-y}} dy dx$
4. Solving to get 4e^-3. But the back of the book says the answer is (e^-2 - e^-3)^2. (Headbang)

I really have no clue what I'm doing wrong. The book is very unclear with its examples; it only gives rectangular regions.

Please help. I really need to get this done. And I am still awaiting help on this problem, which I am no closer to solving.
• Oct 12th 2013, 06:05 PM
chiro
Hey phys251.

According to Wolfram Alpha, your integral is correct (when you take 1 - value of integral).

int e^(-x)*e^(-y)dydx, y = 0 to 3 - x, x = 0 to 3, - Wolfram|Alpha

Its always a good idea to check with Wolfram if you need another independent opinion.
• Oct 14th 2013, 12:10 PM
phys251