workers, percentage, minimum number (normal distribution)

Can someone help me with this?

Producing uniform parts, one worker's average monthly number of parts produced is 550 with standard deviation of 14 parts. Workers labor productivity form a normal distribution.

a) What percentage of workers make more than 700 parts per month?

b) Determine the minimum number of parts per month, for which production workwers may get a bonus money, if in the basis of the size of the bonus pool, you can reward only 17% of workers.

thanks in advance.

Re: workers, percentage, minimum number (normal distribution)

Hey Kiiefers.

Hint: Find the probability of getting more than 700 parts per month for one worker and think about what that means for all workers (if all workers are independent).

Note that if you have N things, then getting a frequency given a probability is calculated by multiplying N by p (the probability).