A certain airline finds that 3% of the persons making reservations on a certain flight will not show up for the flight. Consequently their policy is to sell to 76 persons reserved seats on a plane that has exactly 73 seats. What is the probability that for every person who shows up for the flight,there will be a seat available? Ans: 1-[e^-2.28+e^-2.28(2.28)/1!]Is this answer correct? Let me know from this forum.I have solved this problem hastily, so my answer maybe wrong.ok.