Probability with bayes's theorem

Please help with the question. Thank you guys a lot in advance.

Joe Greedy believes that he has found the location where a Spanish galleon that was transporting a gold shipment worth $10 million sank. He estimates that the probability that he has correctly determined the general area where the shipwreck took place is p. If the treasure is indeed in this area, the probability that he would find it during a dive is q. Dives are independent. Each dive costs c thousands of dollars and Joe has enough money to fund N dives.

__Question:__ Use Bayes’ theorem to determine p_k, the conditional probability that the treasure be in the area given that k unsuccessful dives have been made previously.

Re: Probability with bayes's theorem

Hey hiensteve.

Hint: If you have un-successful dives then this means that D = (D1 = unsuccessful AND D2 = unsuccessful ... AND Dk = Unsuccessful) where you want to find P(Treasure In Area|D).

Remember that for independent events P(A and B) = P(A)P(B).

Re: Probability with bayes's theorem

Quote:

Originally Posted by

**chiro** Hey hiensteve.

Hint: If you have un-successful dives then this means that D = (D1 = unsuccessful AND D2 = unsuccessful ... AND Dk = Unsuccessful) where you want to find P(Treasure In Area|D).

Remember that for independent events P(A and B) = P(A)P(B).

Thanks alot for your helps, actually I already did like that:

T: Treasure in the area

F: Treasure is not in the area

Dk: k dives have been made unsuccessfully

Then

Pk=P(T/Dk)={P(T). P(Dk/T)}/ {P(Dk/T).P(T)+ P(F ).P(Dk/F)}

= {(p.q)^k . (1-q)^k }/ {(p.q)^k . (1-q)^k +(1-p.q)^k.1}

P(Dk/T)= (1-q)^k because here Dk will happen in the case T happen, in other words, it means treasure’s in the area or p =1.

P(Dk/F)= 1 because here Dk will happen in the case T happen, in other words, it means treasure’s not in the area and k dives will be unsuccessful definitely, or q = 0->(1-p.q)^k = 1

Please advise whether i did it right or not,

Thanks alot in advance,

Re: Probability with bayes's theorem

Isn't P(T) = p and P(F) = 1 - p?

Re: Probability with bayes's theorem

Actually i'm thinking about " the area given that k unsuccessful dives have been made previously", i wonder the area is the general area which mentioned above, or the area where k unsuccessful dives has been carried out (i mean sub-areas of the general area), so if like that, the answer will be different and P(T) # p and P(F) # 1 - p.