Figured it out thanks
Last edited by peruvian; February 27th 2013 at 06:43 PM.
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Do you just do P(S^2>2sigma^2)=((sigma^2 X^2)/(n-1)>2sigma^2). Then sigmas cancel and you are left with P(X^2>2(n-1))=?
Is this how you do it? By X^2 i mean the chi-squared dis
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