Candidates A and B are running for office and 55% of the electorate favor candidate B. What is the probability that in a sample of size 100 at least one-half of those sampled will favor candidate A?

Here's what I did:

Let X_i = 1 if the ith person voted for A.

S_100 = X_1 + X_2 + X_3 + ... + X_100

P(S_100 >= 50) = 1 - P(S_100 <= 49)

= 1 - P([S_100 - 100(.45)]/sqrt(100*.45*.55) <= [49 + 1/2 - 100(.45)]/sqrt(100*.45*.55)) #transform into standard norm rv

= 1-P(Z<=0.9045)

= 1-z(0.9045) #z is the standard normal function phi

= 1-0.817

= 0.183

However, the book's solution is 0.133. I don't know how to arrive at that solution. Can someone go through this problem step by step. Thanks!