You need to use a table of normal distribution values to evaluate these.

First you need to change to the

**standard** normal distribution: if x has mean $\displaystyle \mu$ and standard deviation $\displaystyle \sigma$ then the $\displaystyle z= \frac{x- \mu}{\sigma}$ has the

**standard** normal distribution. If you are asked a problem like this, I suspect you have already been taught this and that your text has a table of the standard normal distribution in the back. If not there is one here:

Standard Normal Distribution Table.