Originally Posted by

**0123** Oh no, no, no! I think I got it now..

You mean those probabilities are different because:

if I tell you

-"tell me the probability that the third and fifth out of 5 trials are successes"

you anwer me " Okay. just the 3rd and fifth"

-"yes"

-"So it is just ONE case, you want that? so you have the probability of one possible cpmbinations(out of all that are possibile) (all combinattions having the same likelyhood, the same probability"

Good, then I tell you- "tell me the prob that out of 5 trials you have 2 successes"

you will tell me- " Well, there are x combinations that will give you 2 successes, each combination is equaly likely. You do not care which you are taking. So clearly let's multiply all the times we are lucky(=all the possible combinations that makes us succees) times each combination probability. And there you go."

Yes, yes, it should be like this. Am I right Captain, am I right?? Have I got it now?