Im stuck on a question where I must find the coefficient of determination and then interpret the resulting value.

The value of the correlation coefficient is 0.916

Help is appreciated

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- Oct 11th 2007, 08:25 PMlumberjackjimCoefficient of Determination
Im stuck on a question where I must find the coefficient of determination and then interpret the resulting value.

The value of the correlation coefficient is 0.916

Help is appreciated - Oct 11th 2007, 08:48 PMtopsquark
- Oct 11th 2007, 08:54 PMlumberjackjim
thanks a lot, I was unaware of how incredibly easy that is. this next one seems even more confusing to me though

*Regression Analysis: Larvae versus Stumps*

*The regression equation is*

*Larvae = - 1.29 + 11.9 Stumps*

*Predictor Coef SE Coef T P*

*Constant -1.286 2.853 -0.45 0.657*

*Stumps 11.894 1.136 10.47 0.000*

*S = 6.41939 R-Sq = 83.9% R-Sq(adj) = 83.1%*

*Analysis of Variance*

*Source DF SS MS F P*

*Regression 1 4514.4 4514.4 109.55 0.000*

*Residual Error 21 865.4 41.2*

*Total 22 5379.8*

*Unusual Observations*

*Obs Stumps Larvae Fit SE Fit Residual St Resid*

*10 5.00 56.00 58.18 3.43 -2.18 -0.40 X*

*X denotes an observation whose X value gives it large influence.*

How does the value of the Coefficient of Determination included in this

output compare with that in the previous question?

Based on the regression line obtained, predict the number of larvae clusters for a circular plot in which there were four stumps.

- Oct 11th 2007, 09:40 PMCaptainBlack
The R^2 value is the same as in your first question to the precission it is quoted

in this question 83.9% is 0.839. The corrected R^2 is little different.

The prediction is obtained by plugging 4 in for the number of stumps in the

regression equation:

Larvae = - 1.29 + 11.9 Stumps = -1.29 + 47.6 = 46.31

RonL - Oct 11th 2007, 09:47 PMlumberjackjim
thanks alot