Re: Binomial distribution
Why not upload the image here?
Re: Binomial distribution
Hey KarlssonKK.
The asymptotic distribution results are such that (X - E[X])/SQRT(Var(X)) ~ N(0,1).
So to start off, can you calculate the mean and the variance of your distribution? Using this result, can you then construct a corrected interval (remember that for a binomial, you should find a probability corresponding to 64.5 and not 64 because of the disjoint nature of the binomial)?
1 Attachment(s)
Re: Binomial distribution
Re: Binomial distribution
Quote:
Originally Posted by
chiro
Hey KarlssonKK.
The asymptotic distribution results are such that (X - E[X])/SQRT(Var(X)) ~ N(0,1).
So to start off, can you calculate the mean and the variance of your distribution? Using this result, can you then construct a corrected interval (remember that for a binomial, you should find a probability corresponding to 64.5 and not 64 because of the disjoint nature of the binomial)?
Yes I can calculate the variance but I'm note sure thats the way to go, but if I do, what do I do then?
and what do you mean by finding a propability corresponding to 64,5? I understand that I should not include 65 since it is
<60 and not =<60.
Re: Binomial distribution
Quote:
Originally Posted by
MaxJasper
How did you calculate this?
Re: Binomial distribution
Re: Binomial distribution
The reason you should calculate the standard deviation (and mean) is that a binomial distribution with large number of 'trials' can be approximated by the normal distribution with the same mean and standard deviation.
Re: Binomial distribution
Quote:
Originally Posted by
chiro
you should find a probability corresponding to 64.5 and not 64 because of the disjoint nature of the binomial)?
I think that should be 65.5.
Using the binomial calculation above we get about 0.1629.
Using the normal approximation we get about 0.1631.
Re: Binomial distribution
If the problem is to find the probability that the number of "successes" is 64, then you should use the normal approximation to find the probability that x is between 64.5 and 65.5.
Re: Binomial distribution
Yes it should have been 65.5.