never mind, my prof said the answer key was incorrect. What i had was the correct answer.
I'm having some trouble trying to figure out this question which deals with two population samples. The actual question is as follows:
I know the z statistic is:On Assignment 2 we had n = 342, Σx = 6552 and Σx2 = 127552. On Assignment 3 we had n = 311, Σx = 3667 and Σx2 = 53389. Suppose I want to test H0: μ2-μ3 = 0 against Ha: μ2-μ3 ≠ 0 at a significance level of α=0.05. What is the z-statistic and the conclusion.
z = [(x̄1-x̄2)-D0] / sqrt([s12/n] + [s22/n])
where x̄ = Σx/n
and where s2 = [Σx2 - (Σx)2/n] / n-1
but I'm not exactly sure how I'm supposed to get the correct answer. The Solutions to this are as follows:
[quote]1.4588, -3.5045, do not reject H0 [/quote]
So, I plugged in plugged in the values and I get the following:
x̄1 = 6552/342 = 19.158
x̄2 = 3667/311 = 11.79099
D0 = 0
s12 = [127552 - (65522/342)] / 341 = 5.9515
s22 = [53389 - (36672/311)] / 310 = 32.7465
So then if you plug in everything, you get:
z = [(19.158-11.79099)-0] / sqrt([5.9515/342] + [32.7465/311])
z = 21.029
and since the equation implies the rejection regions lie within the tail ends of the normal distribution, a/2 = 0.025 -> this means the non-rejection zone is μ ± 1.96
this is where I get lost...