Hello people, i need some help
This is the Question:
Check the truth of the following statement: if P(A)=2/3 P(B) , P(B)=3/8 P(C) and P(C) = 2/3, then the events are mutually exclusive per two. To be honest, i cant understand that "per two" phrase.
So , two events in order to be mutual exclusive, A /\ B = 0 , P(A\/B) = P(A) + P(B)
I am not sure how to begin solving this. i noticed also that P(A) + P(B) + P(C) > 1 (13/12).
Thanks in advance ;-)
After some thought....
= P(A)+P(B)+P(C) - P(A/\B) -P(A/\C)-P(B/\C) +P(A/\B/\C)
So, if the events are mutually exclusive, then P(A/\B)=P(A/\C)=P(B/\C)=P(A/\B/\C) Is it alright up to this point ?
Then, i conclude that : = P(A)+P(B)+P(C) .
BUT P(A)+P(B)+P(C) = 13/12 . So if my calculation is right, P(A)+P(B)+P(C) > 1 implies that > 1 . Thats against the basic axiom of probability.
Thus, there is no truth on the given statement.
Its this right, or i am missing something?