I'm having trouble understanding this question:

So since all the values of x are laid out, x is a discrete random variable. Since there are only really two distinct probabilities, I'm guessing this would be a binomial distribution.Suppose the random variable x = 1, 2, 3, 4, 5, 6.

In addition suppose

p(1)=p(2) and p(3)=p(4)=p(5)=p(6)

If the mean μ=4.00, then P(2 ≤ x ≤ 3) is:

The binomial distribution formula is: p(x) = nCx * p^{x}* (1-p)^{n-x and since the mean is given, i know the mean = n*p, but I don't know how I'd find either n or p since neither are given any ideas?}