I'm having trouble understanding this question:
So since all the values of x are laid out, x is a discrete random variable. Since there are only really two distinct probabilities, I'm guessing this would be a binomial distribution.Suppose the random variable x = 1, 2, 3, 4, 5, 6.
In addition suppose
p(1)=p(2) and p(3)=p(4)=p(5)=p(6)
If the mean μ=4.00, then P(2 ≤ x ≤ 3) is:
The binomial distribution formula is: p(x) = nCx * px * (1-p)n-x
and since the mean is given, i know the mean = n*p, but I don't know how I'd find either n or p since neither are given